SOLUTION: The length of a rectangle is three times its width. If the perimeter is at most 112 centimeters, what is the greatest possible value for the width?
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Question 559917: The length of a rectangle is three times its width. If the perimeter is at most 112 centimeters, what is the greatest possible value for the width? Answer by bluemockingjay7(41) (Show Source):
You can put this solution on YOUR website! l = 3w
w = w
p= x at most 112
3w + w < 112 (ill represent it in < )
2(3w + w) < 112
6w + 2w < 112
8w < 112
8w/8 < 112/8
w < 14
the width must be at most 14. (14, 13, 12, 11, 10....)
greatest possible value = 14
