SOLUTION: Find solutions for: (sin(2x)+cos(2x))^2=1

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Question 559106: Find solutions for: (sin(2x)+cos(2x))^2=1
Answer by lwsshak3(11628) About Me  (Show Source):
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Find solutions for: (sin(2x)+cos(2x))^2=1
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(sin(2x)+cos(2x))^2=1
sin(2x)+cos(2x)^2=1
sin(2x)+1-sin(2x)^2=1
sin(2x)-sin(2x)^2=0
sin(2x)(1-sin(2x))=0
sin (2x)=0
2x=0
x=0
or
1-sin(2x)=0
sin(2x)=1
2x=π/2
x=π/4