Question 558916: Suppose tanx= square root of 2 and the terminal side of the angle lies in quadrant 2, What would the cosx, cotx, cscx, and secx equal?
Found 2 solutions by Alan3354, stanbon:
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! Suppose tanx= square root of 2 and the terminal side of the angle lies in quadrant 2, What would the cosx, cotx, cscx, and secx equal?
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The tangent is + in Q1 and Q3.
It can't be sqrt(2) in Q2.
Answer by stanbon(75887)  (Show Source):
You can put this solution on YOUR website! Suppose tanx = square root of 2 and the terminal side of the angle lies in quadrant 2, What would the cosx, cotx, cscx, and secx equal?
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Note: y is positive and x is negative in the 2nd quadrant.
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tan(w) = y/x = -sqrt(2)/-1 implies that y = -sqrt(2) and x = -1
Then r = sqrt[(-sqrt(2))^2 + 1^2] = sqrt(3)
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sin(w) = y/r = sqrt(2/3)
cos(w) = x/r = -1/sqrt(3)
tan(w) = y/x = sqrt(2)/-1 = -sqrt(2)
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csc(w) = r/y = sqrt(3)/sqrt(2) = sqrt(3/2)
sec(w) = r/x = -sqrt(3)
cot(w) = x/y = -1/sqrt(2)
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Cheers,
Stan H.
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