SOLUTION: A 12 cm square is cut along a diagonal to create two right triangles. Find the perimeter of each triangle to the nearest tenth of a centimeters.
Algebra ->
Triangles
-> SOLUTION: A 12 cm square is cut along a diagonal to create two right triangles. Find the perimeter of each triangle to the nearest tenth of a centimeters.
Log On
Question 558833: A 12 cm square is cut along a diagonal to create two right triangles. Find the perimeter of each triangle to the nearest tenth of a centimeters. Answer by mananth(16946) (Show Source):
You can put this solution on YOUR website! the diagonal of square bisects the square
the diagonal is the hypotenuse of triangle with the sides as leg1 & leg2
Hypotenuse ^2= leg1^2+leg2^2
leg1 = 12 cm
Leg2^2= 12 cm
Hypotenuse^2 12 ^2 + 12 ^2
Hypotenuse^2 144 + 144
Hypotenuse^2 288
take the square root
Hypotenuse= 16.97 cm
=17
Perimeter = 17+12+12= 41 cm
