SOLUTION: Suppose a baseball is shot up from the ground straight up with an initial velocity of 32 feet per second. A function can be created by expressing distance above the ground, s, as a
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Question 55874: Suppose a baseball is shot up from the ground straight up with an initial velocity of 32 feet per second. A function can be created by expressing distance above the ground, s, as a function of time, t. This function is s = -16t2 + v0t + s0
• 16 represents ½g, the gravitational pull due to gravity (measured in feet per second 2).
• v0 is the initial velocity (how hard do you throw the object, measured in feet per second).
• s0 is the initial distance above ground (in feet). If you are standing on the ground, then s0 = 0.
a) What is the function that describes this problem?
Answer:
b) The ball will be how high above the ground after 1 second?
Answer:
Show work in this space.
c) How long will it take to hit the ground?
Answer:
Show work in this space.
d) What is the maximum height of the ball?
Answer:
Show work in this space.
You can put this solution on YOUR website! Hi Tine,
Suppose a baseball is shot up from the ground straight up with an initial velocity of 32 feet per second. A function can be created by expressing distance above the ground, s, as a function of time, t. This function is s = -16t2 + v0t + s0
• 16 represents ½g, the gravitational pull due to gravity (measured in feet per second 2).
• v0 is the initial velocity (how hard do you throw the object, measured in feet per second).
• s0 is the initial distance above ground (in feet). If you are standing on the ground, then s0 = 0.
a) What is the function that describes this problem?
Answer:
v0=32 and s0=0
b) The ball will be how high above the ground after 1 second?
Answer: 16 ft
Show work in this space.
s(1)=-16+32
s(1)=16 ft
c) How long will it take to hit the ground?
Answer: t=2s
Show work in this space.
16t=0 and -t+2=0
16t/16=0/16 and -t+2-2=0-2
t=0 and -t=-2
t=0 s and t=2 s
At t=0s the ball was thrown and at t=2s the ball hit the ground.
d) What is the maximum height of the ball?
Answer: 16 ft.
Show work in this space.
The maximum height is the vertex of the parabola. We find the t value of the vertex by the formula:
t=1 at t=1s the ball reaches its maximum height.
s(1)=16 ft
(