SOLUTION: A rectangle is twice as long as it is wide. If its length and width are both decreased by 4 cm, it's area is decreased by 164 cm2. Find it's original dimensions.

Algebra ->  Test -> SOLUTION: A rectangle is twice as long as it is wide. If its length and width are both decreased by 4 cm, it's area is decreased by 164 cm2. Find it's original dimensions.      Log On


   



Question 558675: A rectangle is twice as long as it is wide. If its length and width are both decreased by 4 cm, it's area is decreased by 164 cm2. Find it's original dimensions.
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
width = w
length = l
l/w = 2
l=2w
Area = l*w
=2w^2
(l-4)*(w-4)= 2w^2-164
(2w-4)(w-4)=2w^2-164
2w^2-8w-4w+16=2w^2-164
-12w=-180
/12
w=15cm
length = 30cm