SOLUTION: The dimensions of cylinder B are 4 times the dimensions of cylinder A. If the surface area of cylinder A is 36 cm2, what is the surface area of cylinder B?

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Question 558652: The dimensions of cylinder B are 4 times the dimensions of cylinder A.
If the surface area of cylinder A is 36 cm2, what is the surface area of cylinder B?
Answer by mananth(16946) About Me  (Show Source):
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Cylinder A surface area = 2pir1(r1+h1)

Cylinder B surface area = 2pir2(r2+h2)=x
r2=4r1
h2=4h1
surface area of cylinder B = 2pi*4r1(4r1+4h1)
+%28%282%2Api%2Ar1%28r1%2Bh1%29%29%2F%282pi%2A4r1%284r1%2B4h1%29%29%29=+36%2Fx
%28%28r1%2Bh1%29%2F%284%2A4%28r1%2Bh1%29%29%29=+36%2Fx
x=36*16
x= 5766 cm^2