SOLUTION: John drove to a distant city in 5 hours. When he returned, there was less traffic, and the trip took only 3 hours. If John averaged 26 Mph faster in the return trip, how fast did h
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-> SOLUTION: John drove to a distant city in 5 hours. When he returned, there was less traffic, and the trip took only 3 hours. If John averaged 26 Mph faster in the return trip, how fast did h
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Question 558650: John drove to a distant city in 5 hours. When he returned, there was less traffic, and the trip took only 3 hours. If John averaged 26 Mph faster in the return trip, how fast did he drive each way? Answer by josmiceli(19441) (Show Source):
You can put this solution on YOUR website! Let = distance to city
Let = his speed going to the city
given:
Going to city:
Coming back:
By substitution:
He drove 39 mi/hr to the city and 65 mi/hr coming back
