SOLUTION: between 1970 and 1990, missouri's population increased at the rate of0.47%per year. thepopulation,p, in year t is given by
p = 4,903,000 * 1.0047t where t=0 corresponds to 198
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-> SOLUTION: between 1970 and 1990, missouri's population increased at the rate of0.47%per year. thepopulation,p, in year t is given by
p = 4,903,000 * 1.0047t where t=0 corresponds to 198
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Question 55854This question is from textbook heath algebra I an intergrated approach
: between 1970 and 1990, missouri's population increased at the rate of0.47%per year. thepopulation,p, in year t is given by
p = 4,903,000 * 1.0047t where t=0 corresponds to 1980. find the populationin 1970,1980, and 1990. i understand that 1980 = 4,903,000 but can't
figure out the formula to get the correct answers. This question is from textbook heath algebra I an intergrated approach
You can put this solution on YOUR website! Double check your book for the given terms. Since 1970 is the first year, it should be the 0 value.
t=0 is 1970
t=10 is 1980
t=20 is 1990
Plug 10 in for t
Multiply
Multiply again
Assuming that t=10 for 1980 ... this is the population.
(