SOLUTION: Find equation having the slope and point given:
m=4/5,(2-4)
I get to y+4=4/5(x-2)
rewrite as y+4-4= 4/5x-2-4
rewrite as y=4/5x-6 Is this correct?
I'm lost from here
They sa
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-> SOLUTION: Find equation having the slope and point given:
m=4/5,(2-4)
I get to y+4=4/5(x-2)
rewrite as y+4-4= 4/5x-2-4
rewrite as y=4/5x-6 Is this correct?
I'm lost from here
They sa
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Question 558390: Find equation having the slope and point given:
m=4/5,(2-4)
I get to y+4=4/5(x-2)
rewrite as y+4-4= 4/5x-2-4
rewrite as y=4/5x-6 Is this correct?
I'm lost from here
They say the answer is y=4/5x-28/5
How do you get the -28?????
Thank you Answer by Theo(13342) (Show Source):
rewrite as y+4-4= 4/5x-2-4
this statement is not right.
you took the (x-2) out of the parentheses which messed up your equation.
it should have stayed in the parentheses until you were ready to remove it using the distributive law of multiplication.
it should have been:
y + 4 - 4 = (4/5)*(x-2) - 4
you then need to simplify by multiplying the factors out using the distributive law of multiplication to get:
y = (4/5)*x - (4/5)*2 - 4 which simplifies to:
y = (4/5)*x - (8/5) - 4
since 4 is equivalent to 20/5, your equation becomes:
y = (4/5)*x - (8/5) - (20/5)
you can now combine the fractions with the same denominator to get:
y = (4/5)*x - (28/5)
