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Question 558179: what equation gaes through (-10,3) and is perpendicular t y = 5x - 7
Answer by mananth(16949)   (Show Source):
You can put this solution on YOUR website! y = 5 x + -7
Compare this equation with y=mx+b
slope m = 5
The slope of a line perpendicular to the above line will be the negative reciprocal -1/5
m1*m2=-1
m= - 1/5 ,point ( -10 , 3 )
Find b by plugging the values of m & the point in
y=mx+b
3 = 2.00 + b
b= 1
m= - 1/5
The required equation is y =- ( 1/ 5)x + 1
m.ananth@hotmail.ca
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