Question 557695: How do you solve this linear equation using substitution?
X-y=11
5x-4y=5 Found 2 solutions by stanbon, mananth:Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! How do you solve this linear equation using substitution?
X-y=11
5x-4y=5
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x = y+11
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Substitute for "x" and solve for "y":
5(y+11)-4y = 5
5y+55-4y = 5
y = -50
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Solve for "x":
x = y + 11
x = -50 + 11 = -39
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Cheers,
Stan H.
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You can put this solution on YOUR website! 5 x -4 y = 5 .............1
1 y = 11 -1 x ---------2
/ 1 =
y = 11 -1 x
Substitute y in (1)
5 x -4 ( 11 -1 x ) =
5 x -44 + 4 x = 5
5 x + 4 x = 5 44
9 x = 49
/ 9
x= 49/9
Plug the value of x in (1)
5 x -4 y = 5
5 * 49/9 -4 y = 5
245/9 -4 y = 5
-4 y = 5-(249/9)
-4y=-204/9
/ -4
y= 51/9
m.ananth@hotmail.ca
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