SOLUTION: Richard found three consecutive even integers such that 7 times the sum of the first and third was 48 less than 10 times the second. What were the integers?
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Question 557671: Richard found three consecutive even integers such that 7 times the sum of the first and third was 48 less than 10 times the second. What were the integers? Answer by josmiceli(19441) (Show Source):
You can put this solution on YOUR website! Call the consecutive even integers , , and
given:
The consecutive even integers are -10, -12, and -14
OK
