SOLUTION: Not from a text book, from worksheet.
Find four consecutive intergers such that twice the sume of the two greater intergers exceeds three times the first by 91?
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-> SOLUTION: Not from a text book, from worksheet.
Find four consecutive intergers such that twice the sume of the two greater intergers exceeds three times the first by 91?
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Question 55764: Not from a text book, from worksheet.
Find four consecutive intergers such that twice the sume of the two greater intergers exceeds three times the first by 91? Answer by ankor@dixie-net.com(22740) (Show Source):
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Find four consecutive intergers: x, (x+1), (x+2), (x+3); such that
:
twice the sum of the two greater intergers exceeds three times the first by 91?
2[(x+3)+(x+2)] = 3x + 91
:
2(2x + 5) = 3x + 91
:
4x + 10 = 3x + 91
:
4x - 3x = 91 - 10
:
x = 81
:
:
Check: 2(83+84) = 3(81) + 91
334 = 243 + 91
