SOLUTION: please help me with my Math HW i cant do it...
A man is twice as old as his son. If 9 years ago the sum of their ages was 66 years, find their present ages.
Thanks guys! plea
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A man is twice as old as his son. If 9 years ago the sum of their ages was 66 years, find their present ages.
Thanks guys! plea
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Question 557387: please help me with my Math HW i cant do it...
A man is twice as old as his son. If 9 years ago the sum of their ages was 66 years, find their present ages.
Thanks guys! please help! Answer by bluemockingjay7(41) (Show Source):
You can put this solution on YOUR website! present age:
son = x
man = 2x
age 9 years ago:
son = x - 9
man = 2x- 9
sum = 66 years
x - 9 + 2x - 9 = 66
3x - 18 = 66
3x = 66 + 18
3x = 84
3x/3 = 84/3
x = 28
age 9 years ago:
son = 28 - 9 = 19
man = 2(28) - 9 = 56 - 9 = 47
19 + 47 = 66
66 = 66
present age:
son = 28
man 2(28) = 56
