SOLUTION: The perimeter of a rectangle is 50ft. The lenght is 9 more than the width. Find the legnth and width
Algebra
->
Rectangles
-> SOLUTION: The perimeter of a rectangle is 50ft. The lenght is 9 more than the width. Find the legnth and width
Log On
Geometry: Rectangles
Geometry
Solvers
Solvers
Lessons
Lessons
Answers archive
Answers
Click here to see ALL problems on Rectangles
Question 556944
:
The perimeter of a rectangle is 50ft. The lenght is 9 more than the width. Find the legnth and width
Answer by
JBarnum(2146)
(
Show Source
):
You can
put this solution on YOUR website!
p=50
50=2(l+w)
l=9+w
50=2(9+w+w)
50=18+4w
32=4w
8=w
17=l