SOLUTION: my problem: Where would you expect the vertex on the graph Y= (x-4)^2 +5 to be? Explain why? Thank You

Algebra ->  Test -> SOLUTION: my problem: Where would you expect the vertex on the graph Y= (x-4)^2 +5 to be? Explain why? Thank You      Log On


   

Question 556844: my problem: Where would you expect the vertex on the graph Y= (x-4)^2 +5 to be? Explain why?
Thank You
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
my problem: Where would you expect the vertex on the graph Y= (x-4)^2 +5 to be? Explain why?
The graph is a parabola opening upward.
It has a minimum point at its vertex.
--
The smallest value y can have occurs
when x = 4.
That y-value is 5
---
So the vertex is at (4,5)
===============================
Cheers,
Stan H.
============