SOLUTION: Find all solutions in [0, 2pi) to the equation 2sin(2theta)= - square root of 3.

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Question 556787: Find all solutions in [0, 2pi) to the equation 2sin(2theta)= - square root of 3.
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
ind all solutions in [0, 2pi) to the equation 2sin(2theta)= - square root of 3
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use x in place of theta
2sin2x=-√3
sin2x=-√3/2
2x=4π/3 and 5π/3 (in quadrants III and IV where sin<0
x=2π/3 and 5π/6