Question 55662: To avoid hitting the ball out, a tennis player in one corner of the 312 yd squared court hits the ball to the farthest corner of the opponent
s court. If the length, L, of the tennis court is 2 yd. longer than twice the width, then how far did the player hit the ball?
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! To avoid hitting the ball out, a tennis player in one corner of the 312 yd squared court hits the ball to the farthest corner of the opponent
s court. If the length, L, of the tennis court is 2 yd. longer than twice the width, then how far did the player hit the ball?
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Let the width be "w".
Then the length = 2w+2
Area = w(2w+2)=2w^2+2w=312
Divide thru by 2 to get:
w^2+w-156=0
(w+13)(w-12)=10
width = 12 yrds.
Length = 2(12)+2=26 yrds
Use Pythagoras to find the diagonal distance:
d=sqrt(12^2+26^2)
d=sqrt820
distance = 28.64 yrds.
Cheers,
Stan H.
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