Question 55651This question is from textbook
: I really don't know how to go over this. I am confuse about the linear triplet part.Please explain...Thanks.
DNA (Deoxyribonucleic acid) is made of nucleotides, and each nucleotide can contain any one of these nitrogenous bases: A(Adenine), G (Guanine), C (cytosine), T(thymine). If one of these four bases(A,G,C,T) must be selected three times to form a linear triplet,how many different triplets are possible? Note that all four bases can be selected for each of the three components of the triplet.
This question is from textbook
Answer by fanks(6) (Show Source):
You can put this solution on YOUR website! At first, when I read, I understood that you must take one of the four bases three times to form a triplet. However, that would be pretty lame, because then you have only four different possible triplets (AAA, GGG, CCC, and TTT).
So, I suppose, either it is a clumsy wording or there is a language barrier for me, but what is meant is simply that you use four different bases to form a triplet - arranged string of letters A, G, C, or T.
In that case you can take one of four letters as the first one, one of four letters as the second one, and as the third one.
Thus you get different possible triplets.
|
|
|