SOLUTION: a plane flew a triangular route for a total distance of 149 miles. if the longest leg of the flight is twice the length of the shortest leg and the third leg is one mile less than
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Question 556164: a plane flew a triangular route for a total distance of 149 miles. if the longest leg of the flight is twice the length of the shortest leg and the third leg is one mile less than the longest leg, then ehat is the lenght of the longest leg? Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! a plane flew a triangular route for a total distance of 149 miles. if the longest leg of the flight is twice the length of the shortest leg and the third leg is one mile less than the longest leg, then ehat is the lenght of the longest leg?
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x = shortest leg
2x = longest leg
2x-1 = 3rd leg
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5x - 1 = 159
x = 30
longest leg = 60
