SOLUTION: Trains A and B are traveling in the same direction on parallel tracks. Train A is traveling at 100 mph and train B is traveling at 110 mph. Train A passes a station at 4:20 AM.
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Question 556073: Trains A and B are traveling in the same direction on parallel tracks. Train A is traveling at 100 mph and train B is traveling at 110 mph. Train A passes a station at 4:20 AM. If train B passes the same station at 4:50 AM, what time will train B catch up to train A? Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! Trains A and B are traveling in the same direction on parallel tracks.
Train A is traveling at 100 mph and train B is traveling at 110 mph.
Train A passes a station at 4:20 AM.
If train B passes the same station at 4:50 AM, what time will train B catch up to train A?
:
From the given information, we know that Train B is 30 min behind A at at 4:20AM
therefore Train B is: * 110 = 55 miles behind Train A at that time.
:
Let t = time required for Train B to catch Train A
:
Write a distance equation; dist = speed * time
:
Train B dist = Train A dist + 24 mi
110t = 100t + 55
110t - 100t = 55
10t = 55
t =
t = 5.5 hrs for B to catch A
:
Convert 5.5 hrs to hrs and minutes: 5 hrs 30 min
:
Find the time from 4:20 am:
4:20 + 5:30 = 9:50 am Train B catches Train A
