Question 55558: hi, i'm having trouble with one specific problem which you use "substitution" in order to solve two equations by using inverse matrices. My teacher told us the answer, but not how to solve it. the answer he gave is: (2,4,8) and the equations are >>>>>sorry it wouldn't show up if i highlighted it>>>>>> 2|x-1|-|y+3|=-1 and 5|x-1|-2|y+3|=1 < he told us to 'substitute' to make it easier, for example make a= |x-1| and b=|y+3| that way it would be  and  but when i do that, and i create the matrices, the inverse always ends up with [[3][7]] ex: a=3 b=7 . but thats where i lose it? i don't understand how he got (2,4,8) when x=4, -2 and y= 4, -10. so if you could help me, or show me what i did wrong and what steps to take please help
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! The answer he gave is: (2,4,8) and the equations are >>>>>sorry it wouldn't show up if i highlighted it>>>>>> 2|x-1|-|y+3|=-1 and 5|x-1|-2|y+3|=1 < he told us to 'substitute' to make it easier, for example make a= |x-1| and b=|y+3| that way it would be and but when i do that, and i create the matrices, the inverse always ends up with [[3][7]] ex: a=3 b=7 . but thats where i lose it? i don't understand how he got (2,4,8) when x=4, -2 and y= 4, -10. so if you could help me, or show me what i did wrong and what steps to take please help
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I agree with your work. The x,y pairs that work are (4,4) and (2,-10)
Cheers,
Stan H.
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