SOLUTION: 16^(2x+3)=64^(x+2) Can you show me how to do the problem, not just the answer?

Algebra ->  Trigonometry-basics -> SOLUTION: 16^(2x+3)=64^(x+2) Can you show me how to do the problem, not just the answer?       Log On


   

Question 555246: 16^(2x+3)=64^(x+2)
Can you show me how to do the problem, not just the answer?
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
16^(2x+3)=64^(x+2)


(4^2)^(2x+3)=(4^3)^(x+2)


4^(2(2x+3))=4^(3(x+2))


Since the bases are equal, the exponents are equal.


2(2x+3)=3(x+2)


4x+6=3x+6


4x=3x+6-6


4x-3x=6-6


x=6-6


x=0

If you need more help, email me at jim_thompson5910@hotmail.com

Also, please consider visiting my website: http://www.freewebs.com/jimthompson5910/home.html and making a donation. Thank you

Jim