SOLUTION: the sum of two numbers is two. the difference between eight and twice the smaller number is two less than four times the larger. Find the two numbers

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Question 55515: the sum of two numbers is two. the difference between eight and twice the smaller number is two less than four times the larger. Find the two numbers

Found 2 solutions by checkley71, ankor@dixie-net.com:
Answer by checkley71(8403) (Show Source):
You can put this solution on YOUR website!
X+Y=2
8-2X=4Y-2
X=2-Y
8-2(2-Y)=4Y-2
8-4+2Y=4Y-2
4Y-2Y=8-4+2
2Y=6
Y=6/2
Y=3
X+3=2
X=2-3
X=-1
PROOF
8-2*-1=4*3-2
8+2=12-2
10=10

Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website!
the sum of two numbers is two.
x + y = 2
x = (2 - y); substitute for x in the 2nd equation
:
the difference between eight and twice the smaller number is two less than four times the larger. Let the smaller number be x:
8 - 2x = 4y - 2
-2x - 4y = -2 - 8
:
Get rid of all the negatives, mult eq by -1:
2x + 4y = +10
:
Substitute (2-y) for x:
2(2-y) + 4y = 10
4 - 2y +4y = 10
2y = 10 -4
y = 6/2
y = +3
:
Use x + y = 2 to find the value of x:
x + 3 = 2
x = 3 -3
x = -1
:
:
Check the solutions:
8 - 2x = 4y - 2
8 - 2(-1) = 4(3) - 2
8 + 2 = 12 - 2