SOLUTION: Find the equation of the normal and tangent to the curve at the given point:
f(x) = x^3 - 2(x^2) + 4 , (2,4)
Thank you
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-> SOLUTION: Find the equation of the normal and tangent to the curve at the given point:
f(x) = x^3 - 2(x^2) + 4 , (2,4)
Thank you
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Question 555121: Find the equation of the normal and tangent to the curve at the given point:
f(x) = x^3 - 2(x^2) + 4 , (2,4)
Thank you Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! Find the equation of the normal and tangent to the curve at the given point:
f(x) = x^3 - 2(x^2) + 4 , (2,4)
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f'(x) = 3x^2 - 4x
f'(2) = 4
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Use y = mx + b and the point
4 = 4*2 + b
b = -4
--> y = 4x - 4 is tangent
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Use the same method for the perpendicular.
