SOLUTION: 1.Factor by grouping, if possible, and check. 20g^3-4g^2-25g+5 and completely show your work.

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: 1.Factor by grouping, if possible, and check. 20g^3-4g^2-25g+5 and completely show your work.      Log On


   



Question 555019: 1.Factor by grouping, if possible, and check. 20g^3-4g^2-25g+5 and completely show your work.
Found 2 solutions by fcabanski, sarhjo29:
Answer by fcabanski(1391) About Me  (Show Source):
You can put this solution on YOUR website!
20g^3-4g^2-25g+5 | Separate into separate terms.
(20g^3 - 4g^2) (-25g+5) |factor each
4g^2(5g-1) (-5(5g-1)
(4g^2-5)(5g-1) | Plug in 0, 1 and -1 to see both expressions are the same.


35x^2-57x-44 | Think of factors for 35 and for 44. 5+7=35 and 4*11=44 and 2*22=44.
(5x )(7x ) |Can 4 and 11 or 2 and 22 fit in there to give -57x and -44. Yes.
(5x - 11)(7x + 4) | 4*-11=-44 and -11*7x+4*5x=-57. Check some x values to see it's the right factor.


3t^2-3 | 3 is prime so the terms have to be 3t and t and 3 and 1.
(3t-3)(t+1)

If you need help understanding math so you can solve these problems yourself, then one on one online tutoring is the answer ($30/hr). If you need faster solutions with guaranteed detailed answers, then go with personal problem solving ($3.50-$5.50 per problem). Contact me at fcabanski@hotmail.com



Answer by sarhjo29(2) About Me  (Show Source):
You can put this solution on YOUR website!
Factor by grouping, if possible, and check. 20g^3-4g^2-25g+5 and completely show your work.