SOLUTION: The length of a rectangle is 3 inches greater than the width.
A. Write a polynomial that represents the area of the rectangle.
B. Find the area of the
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-> SOLUTION: The length of a rectangle is 3 inches greater than the width.
A. Write a polynomial that represents the area of the rectangle.
B. Find the area of the
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Question 555016: The length of a rectangle is 3 inches greater than the width.
A. Write a polynomial that represents the area of the rectangle.
B. Find the area of the rectangle when the width is 4 inches. Answer by Maths68(1474) (Show Source):
You can put this solution on YOUR website! Length = l
Width = w
The length of a rectangle is 3 inches greater than the width = l = w+3
Area of rectangle = a
A. Write a polynomial that represents the area of the rectangle.
a=lw
a=w(w+3)
a=w^2+3w
w^2+3w-a=0
(B)
Find the area of the rectangle when the width is 4 inches
a=w^2+3w
w=4
a=(4)^2+3(4)
a=16+12
a=28 sq inches
