Question 554897: A shuttle's launch depends on three devices that may fail independently of each other with probabilities 0.01, 0.02, and 0.02, respectively. If any of the key devices fails, the launch will be postponed. Compute the probability for the shuttle to be launched on time, according to its schedule.
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! A shuttle's launch depends on three devices that may fail independently of each other with probabilities 0.01, 0.02, and 0.02, respectively. If any of the key devices fails, the launch will be postponed. Compute the probability for the shuttle to be launched on time, according to its schedule.
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P(launch) = P(none fail) = 0.99*0.98*0.98 = 0.9508
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Cheers,
Stan H.
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