You can put this solution on YOUR website! Two integers: x, (x+2)
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The product of two consecutive even integers is 30 less than 15 times their sum.
x(x+2) = 15[x + (x+2)] - 30
x^2 + 2x = 15(2x + 2) - 30
x^2 + 2x = 30x + 30 - 30
x^2 = 30x - 2x
x^2 = 28x
Divide both sides by x
x = 28 and 30 are the two even integers
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see if that works
28(30) = 15[28+30] - 30
840 = 15(58) - 30
840 = 870 - 30; confirms our our solution