SOLUTION: Given a right triangle with a side of length 4 and a hypotenuse of length 7, find the measure of the two acute angles. (Round to the nearest hundredth.) please help so confus

Algebra ->  Triangles -> SOLUTION: Given a right triangle with a side of length 4 and a hypotenuse of length 7, find the measure of the two acute angles. (Round to the nearest hundredth.) please help so confus      Log On


   



Question 554847: Given a right triangle with a side of length 4 and a hypotenuse of length 7, find the measure of the two acute angles. (Round to the nearest hundredth.)

please help so confused

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Since it's a right triangle, there is a right angle.
That means the sum of the 2 acute angles is
90 degrees. ( 90 + 90 = 180 )
Suppose you want to find the angle which is between
the hypotenuse and the side of length 4.
+cos%28+a+%29+=+4%2F7+
+cos%28+a+%29+=+.5714+
+a+=+cos%5E-1+%28+.5714+%29+ ( this reads " a is the angle whose cosine is .5714 " )
+a+=+55.15+ and
+90+-+55.15+=+34.85+
The acute angles are 55.15 and 34.85 degrees