SOLUTION: The problem says: Arianna took 2 h longer to drive 360 mi on the first day of a trip than she took to drive 270 mi on the second day. If her speed was the same on both days, what
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-> SOLUTION: The problem says: Arianna took 2 h longer to drive 360 mi on the first day of a trip than she took to drive 270 mi on the second day. If her speed was the same on both days, what
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Question 55478: The problem says: Arianna took 2 h longer to drive 360 mi on the first day of a trip than she took to drive 270 mi on the second day. If her speed was the same on both days, what was the driving time each day?
Thank you bunches--
CH Answer by tutorcecilia(2152) (Show Source):
You can put this solution on YOUR website! d=rt [Use the distance formula]
First day: 360 miles=(r)(t+2)
Second day: 270 miles =(r)(t)
.
Since the speed (r) was the same, than
d=rt
r=d/t
so,
r=r or
d/t=d/t [Plug in the values for the first and second day]
360 miles/(t+2) = 270/t [Solve for t]
360/(t+2)=270/t
360t=270(t+2)
360t=270t+540
360t-270t=540
90t=540
t=6 hours on the second day
(t+2)=(6+2)=8 hours on the first day
.
check by plugging the values back into each of the original equations:
