Question 5547: Please help me in graphing this equation. Once again my book shows no examples of this problem.
y = 2^x - 1 Found 2 solutions by longjonsilver, Abbey:Answer by longjonsilver(2297) (Show Source):
You can put this solution on YOUR website! graphing? you mean draw a proper graph? Pick your x-values...put each into the equation to fonf the equivalent y-value. Then plot the points to give you a curve.
I suggest you pick -2, -1, 0, 1, 2, 3, 4, 5. Anything bigger will be too large.
You will get a curve that, starting from the -ve x-direction is nearly horizontal and gets steeper very quickly as x increases past x=1.
You can put this solution on YOUR website! just plug in random values for x and plot the (x,y) coordinates
If x = 1, then y = so y=2 plot the point (1,2)
If x = 0 so y=1 plot the point (0,1)
If x = -1 y = -1/2 plot the point (-1,-1/2)
If x = 2 y = 3 plot the point (2,3)
and so on... the more points you find, the more defined the graph.
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