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Question 55464: write the general equation form of the line which passes through the 2 points: (1,2), (6,7)
Found 2 solutions by tutorcecilia, Edwin McCravy:
Answer by tutorcecilia(2152)   (Show Source):
You can put this solution on YOUR website! Ax+By=C [General equation of a line]
(y-y2)=m(x-x2) [Point-slope equation of a line.]
m=(y-y2)/(x-x2) [Formula for the slope of a line.]
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(1,2), (6,7) [Find the slope of the line with these two points]
m=(7-2)/(6-1)=5/5=1 [Plug-in the values]
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(y-7)=(1)(x-6) [Use the point-slope formula; plug-in the points and slope]
y-7=x-6 [Isolate the numbers]
y-x=-6+7
-x+y=1 [General equation of a line]
.
Check by plugging either set of coordinate points into the formula:
Example: Use (1, 2)
(-(1)+(2))=1
1=1 [checks out]
.
Use (6, 7)
-(6)+7=1
1=1 [Also checks out]
Answer by Edwin McCravy(20056)  (Show Source):
You can put this solution on YOUR website! write the general equation form of the line
which passes through the 2 points: (1,2), (6,7)
You need two formulas:
y2 - y1
m = --------- to find the slope, m, and
x2 - x1
then you substitute the value you get for m, then
substitute the values for x1 and y1. Do not
substitute anything for x and y. Just leave them
variable:
y - y1 = m(x - x1)
(x1,y1) = (1,2), (x2, y2) = (6,7)
so
y2 - y1 7 - 2 5
m = --------- = ------- = --- = 1
x2 - x1 6 - 1 5
Then
y - y1 = m(x - x1) becomes
y - 2 = 1(x - 1)
y - 2 = x - 1
+ 2 + 2
-------------
y = x + 1
That's the equation:
y = x + 1
Edwin
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