SOLUTION: if the terminal side of θ is in quadrant 2 and sinθ=12/13 then how do you find sin(π-θ) sin(π+θ) cosθ cos(π/2-θ) sin-θ

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Question 554364: if the terminal side of θ is in quadrant 2 and sinθ=12/13 then how do you find sin(π-θ)
sin(π+θ)
cosθ
cos(π/2-θ)
sin-θ
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
if the terminal side of θ is in quadrant 2 and sinθ=12/13 then how do you find:
..
In quadrant 2:
sin θ=12/13
cos θ=5/13
..
sin(π-θ)=12/13 (reference angle in quadrant I where sin>0)
sin(π+θ)=-12/13 (reference angle in quadrant IV where sin<0)
cosθ=-5/13 (reference angle in quadrant II where cos<0)
cos(π/2-θ)=sin θ=-12/13 (reference angle in quadrant IV where sin<0)
sin-θ=-12/13 (reference angle in quadrant III where sin<0)
..
note: assume θ is an angle between π and π/2 (quadrant II), then move it accordingly)