SOLUTION: Suppose two distinct parallelograms lie in a plane. What is the LARGEST number of points at which they can intersect? The answer choices are: 2, 4, 6, & 8. I was thinking it

Algebra ->  Parallelograms -> SOLUTION: Suppose two distinct parallelograms lie in a plane. What is the LARGEST number of points at which they can intersect? The answer choices are: 2, 4, 6, & 8. I was thinking it       Log On


   

Question 554341: Suppose two distinct parallelograms lie in a plane. What is the LARGEST number of points at which they can intersect?
The answer choices are: 2, 4, 6, & 8.
I was thinking it was either 2 or 4, but I just can't remember. I've looked everywhere in my notes, and Google is kind of useless :(
Thank you!!
Found 2 solutions by Edwin McCravy, richard1234:
Answer by Edwin McCravy(20056) About Me  (Show Source):
You can put this solution on YOUR website!


It's like the red square and the green square below.  Squares ARE

parallelograms, by the way.  So the answer is ---- (you count 'em):







Edwin

Answer by richard1234(7193) About Me  (Show Source):
You can put this solution on YOUR website!
You can't really guess at it, and notes or Google won't help for this type of question. I would draw something like what the other tutor drew. Note that you can rigorously prove that the answer is at most 8 (presuming no two segments of different parallelograms are the same), but we don't need to go there.