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Question 554303: What is the standard form of 16y^2-36x^2+9=0
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! What is the standard form of 16y^2-36x^2+9=0
16y^2-36x^2=-9
divide by -9
x^2/4-y^2/(9/16)=1
This is an equation of a hyperbola with horizontal transverse axis of the standard form:
(x-h)^2/a^2-(y-k)^2/b^2=1, with (h,k) being the (x,y) coordinates of the center.
For given equation:
center: (0,0)
a^2=4
a=√4=2
b^2=9/16
b=√(9/16)=3/4
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