SOLUTION: A collection of 102 nickels dimes and quarters (all together the coins equal 102) is wortth $13.60. How many quarters are there.

Algebra ->  Complex Numbers Imaginary Numbers Solvers and Lesson -> SOLUTION: A collection of 102 nickels dimes and quarters (all together the coins equal 102) is wortth $13.60. How many quarters are there.      Log On


   



Question 55413: A collection of 102 nickels dimes and quarters (all together the coins equal 102) is wortth $13.60. How many quarters are there.
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
A collection of 102 nickels dimes and quarters (all together the coins equal 102) is wortth $13.60. How many quarters are there.
-------------
Let number of dimes by "x" ; Value of those dimes is 10x cents
Number of quarters is "102-x"; Value of those coins is 25(102-x)=2550-25x cents
EQUATION:
value + value = 1360 cents
10x + 2550-25x = 1360
-15x=-1190
x= 79 1/3
Comment: This is meaningless. You can't have 79 1/3 dimes.
cheers,
Stan H.