Question 553907: Find the Vertices and the foci of the hyperbola. y^2/5-x^2/11=1.
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! Find the Vertices and the foci of the hyperbola. y^2/5-x^2/11=1
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y^2/5-x^2/11=1
This is an equation of a hyperbola with vertical transverse axis of the standard form:
(y-k)^2/a^2-(x-h)^2/b^2=1, (h,k) being the (x,y) coordinates of the center:
For given equation:
center:(0,0)
a^2=5
a=√5≈2.24
..
b^2=11
b=√11≈3.32
..
c^2=a^2+b^2=5+11=16
c=√16=4
..
vertices: (0,0±a), (0,0±√5)=(0,2.24) and (0,-2.24)
foci: (0,0±c), (0,0±4)=(0,4) and (0,-4)
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