SOLUTION: Solve giving real and complex numbers: x^3 - 3x^2 + x - 3 = 0

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Question 553688: Solve giving real and complex numbers:
x^3 - 3x^2 + x - 3 = 0

Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
x%5E3+-+3x%5E2+%2B+x+-+3+=+0
FACTORING BY GROUPING
%28x%5E3+-+3x%5E2%29+%2B+%28x+-+3%29+=+0 --> x%5E2%28x+-+3%29+%2B+%28x+-+3%29+=+0 --> %28x%5E2%2B1%29%28x+-+3%29
The real solution is the solution to x-3=0 --> x=3
The imaginary solutions are the solutions to
x%5E2%2B1=0 --> x=i and x=-i