SOLUTION: A car dealer sold two cars. On the first car he made a 10% profit and on the second car he lost 10%. He sold the cars for $9999 each. What was the overall dollar amount of profit o

Algebra ->  Customizable Word Problem Solvers  -> Misc -> SOLUTION: A car dealer sold two cars. On the first car he made a 10% profit and on the second car he lost 10%. He sold the cars for $9999 each. What was the overall dollar amount of profit o      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 553658: A car dealer sold two cars. On the first car he made a 10% profit and on the second car he lost 10%. He sold the cars for $9999 each. What was the overall dollar amount of profit or loss on the two transactions, or did the dealer break even?
Answer by Maths68(1474) About Me  (Show Source):
You can put this solution on YOUR website!
Total value of two cars = 9999+9999 = 19998
First Car was sold on 10% profit = 9999*10/100=99990/100=999.90
Second Car was sold on 10% loss = 9999*10/100=99990/100=999.90

Total amount of two cars after sale = (value of first car + profit)+ (Value of Second car - loss)
Total amount of two cars after sale = (9999+999.90)+(9999-999.90)
Total amount of two cars after sale = 10998.90+8999.10
Total amount of two cars after sale = 19998


Total value of two cars before sale= Total value of two cars after sale
19998=19998

Dealer broke even.