If cotq = -3/4 and sinq < 0, then the value of cosq is:
The cotangent, being
is negative, and the cotangent is
negative in quadrants II and IV
The sine, being < 0, is negative, and the sine is
negative in quadrants III and IV.
Therefore q is in quadrant IV
The cotangent is
=
So we draw a triangle in quadrant IV with its hypotenuse as
the terminal side of q, its shorter leg x=+3 and its longer leg
y=-4. The shorter leg will be taken positive since it goes right,
and the longer leg will be taken negative because it goes down.
The angle q is indicated by the red arc.
Now we calculate r, the hypotenuse, by the Pythagorean theorem:
r² = x² + y²
r² = (3)² + (-4)²
r² = 9 + 16
r² = 25
r = 5
Now since we want cos(q), we know that cos(q) =
=
.
It is positive as we would expect an angle's cosine to be in quadrant IV.
Edwin