SOLUTION: Solve: {{{sin3xtanx-sin3x=0}}} , {{{0<=x<=3pi/2}}}
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-> SOLUTION: Solve: {{{sin3xtanx-sin3x=0}}} , {{{0<=x<=3pi/2}}}
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Question 553543
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Answer by
lwsshak3(11628)
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sin3xtanx-sin3x=0 , 0<=x<=3π/2
sin3x(tanx-1)=0
sin3x=0
3x=0
x=0 and π
..
tanx-1=0
tanx=1
x=π/4 and 5π/4 (in quadrants I and III where tan>0)