SOLUTION: x to the 6th - 9y to the 2
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Question 553500
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x to the 6th - 9y to the 2
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x^6 - 9y^2 factors out to be (x^3 - 3y)(x^3 + 3y).
If you multiply (x^3 - 3y) by (x^3 + 3y), it will take you back to the given problem. This is how we know when the answer is correct in terms of factoring.
Factoring is the opposite of multiplication.
Understand?