Question 553395: I'm so lost....
"From a bag containing 5 nickels, 9 dimes, and 6 quarters, 7 coins are drawn random all at once. What is the probability of getting 2 nickels, 3 dimes, and 2 quarters?"
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! "From a bag containing 5 nickels, 9 dimes, and 6 quarters, 7 coins are drawn random all at once. What is the probability of getting 2 nickels, 3 dimes, and 2 quarters?"
----
# of ways to get 2 nickels: 5C2 = 10
# of ways to get 3 dimes: 9C3 = 84
# of ways to get 2 quarters: 6C2 = 15
-----
Total # of ways to get 2nick and 3dimes and 2 quarters = 10*84*15 = 12600
-----
#of ways to pick 7 coins randomly from 20 = 20C7 = 77520
----
P(2nick and 3dimes and 2quarters) = 12600/77520 = 0.1625
=================================
Cheers,
Stan H.
=================================
|
|
|
