SOLUTION: A manufacturer of a consumer electronics product expects 2% of units to fail during the warranty period. A sample of 500 independent units is tracked for warranty performance.
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Question 553192: A manufacturer of a consumer electronics product expects 2% of units to fail during the warranty period. A sample of 500 independent units is tracked for warranty performance.
(a) What is the probability that none fails during the warranty period?
(b) What is the expected number of failures during the warranty period?
(c) What is the probability that more than two units fail during the warranty period? Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! A manufacturer of a consumer electronics product expects 2% of units to fail during the warranty period. A sample of 500 independent units is tracked for warranty performance.
Binomial Problem with n = 500 and p(fail) = 0.02 and P(good) = 0.98
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(a) What is the probability that none fails during the warranty period?
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P(x = 500) = 0.98^500 = 0.000041024
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(b) What is the expected number of failures during the warranty period?
Expected number = mean = np = 500*0.02 = 10
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(c) What is the probability that more than two units fail during the warranty period?
P(x >= 3) = 1 - P(0<= x <=2) = 1 - binomcdf(500,0.02,2) = 0.9974
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Cheers,
Stan H.
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