SOLUTION: Hello: Please help me solve the following problem (thank you) divide {{{8x^3+ 8y^3}}}divided by {{(4x^2-4xy+4y^2}}}

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Hello: Please help me solve the following problem (thank you) divide {{{8x^3+ 8y^3}}}divided by {{(4x^2-4xy+4y^2}}}      Log On


   

Question 55309: Hello: Please help me solve the following problem (thank you)
divide
8x%5E3%2B+8y%5E3divided by {{(4x^2-4xy+4y^2}}}
Found 2 solutions by funmath, stanbon:
Answer by funmath(2933) About Me  (Show Source):
You can put this solution on YOUR website!
divide
%288x%5E3%2B+8y%5E3%29%2F%284x%5E2-4xy%2B4y%5E2%29
Factor out the GCF in the numerator and denominator:
%288%2Ax%5E3%2B8%2Ay%5E3%29%2F%284%2Ax%5E2%2B4%2A%28-xy%29%2B4%2Ay%5E2%29
8%28x%5E3%2By%5E3%29%2F%284%28x%5E2-xy%2By%5E2%29%29 The formula for factoring the sum of cubes is:highlight%28u%5E3%2Bv%5E3=%28u%2Bv%29%28u%5E2-uv%2Bv%5E2%29%29.
%284%2A2%28x%2By%29%28x%5E2-xy%2By%5E2%29%29%2F%284%28x%5E2-xy%2By%5E2%29%29 Cancel the things that match between the numerator and denominator:

2%28x%2By%29%2F1
highlight%282%28x%2By%29%29
That's usually all you need, but you could distribute the 2 and get 2x+2y.
Happy Calculating!!!

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
(8x^3+ 8y^3) divided by (4x^2-4xy+4y^2)
[8(x^3+y^3}]/[4(x^2-x+y^2)]
Reduce the 8/4 to get:
[2(x+y)(x^2-xy+y^2)]/[x^2-xy+y^2]
Cancel the x^2-xy+y^2 to get:
2x+2y
Cheers,
Stan H.