SOLUTION: how do you slove this problem ? 2x^2-x=12-x

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Question 553059: how do you slove this problem ?
2x^2-x=12-x
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

2x%5E2-x=12-x Start with the given equation.


2x%5E2-x-12%2B1x=0 Get every term to the left side.


2x%5E2%2B0x-12=0 Combine like terms.


Notice that the quadratic 2x%5E2%2B0x-12 is in the form of Ax%5E2%2BBx%2BC where A=2, B=0, and C=-12


Let's use the quadratic formula to solve for "x":


x+=+%28-B+%2B-+sqrt%28+B%5E2-4AC+%29%29%2F%282A%29 Start with the quadratic formula


x+=+%28-%280%29+%2B-+sqrt%28+%280%29%5E2-4%282%29%28-12%29+%29%29%2F%282%282%29%29 Plug in A=2, B=0, and C=-12


x+=+%28-0+%2B-+sqrt%28+0-4%282%29%28-12%29+%29%29%2F%282%282%29%29 Square 0 to get 0.


x+=+%28-0+%2B-+sqrt%28+0--96+%29%29%2F%282%282%29%29 Multiply 4%282%29%28-12%29 to get -96


x+=+%28-0+%2B-+sqrt%28+0%2B96+%29%29%2F%282%282%29%29 Rewrite sqrt%280--96%29 as sqrt%280%2B96%29


x+=+%28-0+%2B-+sqrt%28+96+%29%29%2F%282%282%29%29 Add 0 to 96 to get 96


x+=+%28-0+%2B-+sqrt%28+96+%29%29%2F%284%29 Multiply 2 and 2 to get 4.


x+=+%28-0+%2B-+4%2Asqrt%286%29%29%2F%284%29 Simplify the square root (note: If you need help with simplifying square roots, check out this solver)


x+=+%28-0%29%2F%284%29+%2B-+%284%2Asqrt%286%29%29%2F%284%29 Break up the fraction.


x+=+0+%2B-+sqrt%286%29 Reduce.


x+=+sqrt%286%29 or x+=+-sqrt%286%29 Break up the expression.


So the solutions are x+=+sqrt%286%29 or x+=+-sqrt%286%29