SOLUTION: {{{(2x^3-7x^2-17x-3)/(2x+3)}}}

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Question 553044: %282x%5E3-7x%5E2-17x-3%29%2F%282x%2B3%29
Answer by TutorDelphia(193) About Me  (Show Source):
You can put this solution on YOUR website!
%282x%5E3-7x%5E2-17x-3%29%2F%282x%2B3%29
Set your paper up like a long division problem

2x+3) 2x^3-7x^2-17x-3
look at your highest power first.
What can I multiply 2x by to get 2x^3?
I can multiply by x^2
So I multiply by x^2 and get 2x^3+3x^2 and I subtract that from 2x^3+3x^2 and get -10x^2 and bring down the -17x
Now looking at -10x^2-17x, what can I multiply 2x by to get -10x^2? -5x
So I multiply by -5x and get -10x^2-15x. Since I'm subtracting and have a negative I reverse the signs and get -2x and bring down the -3
To get -2x-3 I multiply by -1 and get -2x-3 so again, reverse the signs and that all works out evenly
I get x^2-5x-1 as my answer.
This would be easier to diagram out for you, but hopefully this helped. You can also watch this video on dividing polynomials: http://www.khanacademy.org/video/polynomial-division?playlist=ck12.org+Algebra+1+Examples