SOLUTION: A dealer has some hard candy worth 2 dollars a pound and some worth 3 dollars a pound. He wishes to make a mixture of 80 pounds, that he can sell for $2.20 a pound. How many pounds

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: A dealer has some hard candy worth 2 dollars a pound and some worth 3 dollars a pound. He wishes to make a mixture of 80 pounds, that he can sell for $2.20 a pound. How many pounds      Log On


   

Question 552956: A dealer has some hard candy worth 2 dollars a pound and some worth 3 dollars a pound. He wishes to make a mixture of 80 pounds, that he can sell for $2.20 a pound. How many pounds of each kind should he use?
(could you show me the work,too?)
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
price ---------------- quantity
Candy type I 2 ---------------- x Lb
Candy type II 3 ----------------80-xLb
Mixture 2.20% ----------------80

2x+3(80 -x)=2.2 *80

2x+240-3x=176
2x-3x=176-240
-1x=-64
/ -1
x=64 Lb $2.00 Candy type I
16 Lb $3.00 Candy type II